An artist is sculpting a spherical statue that has a diameter of 10 inches. If the clay to sculpt the statue weighs approximately 1.1 oz/in3 what is the weight of the statue to the nearest ounce?

Question

Please round to the nearest tenth! (Please show your work!)  :)

Answer 1

Radius is half the diameter, that is, 10/2=5in. Volume=4π(5³)/3=(4×125)π/3=500π/3in³. (Volume of sphere=(4/3)πr³ where r is its radius.)

Density of the clay=1.1oz/in³, so the weight of the statue=1.1×500π/3=550π/3=575.96in³. (density=weight/volume, so weight=density×volume)

To the nearest tenth this is 576.0in³.

(π (pi) has a value of about 3.1416 and is the constant ratio of the diameter and the circumference of a circle)