find the sixth term of the expansion (1/2x^2-3x^3/4)^10
to do this the easy way remember the first term is (1/2x^2) the second term is (-3x^3/4). Now write the first term to the sixth and the second term to the zero, or the number 1. add the next part by reducing first term by 1 and increasing second term by 1 continue on.
(1/2x^2)^6 + (1/2x^2)^5(-3x^3/4)^1 + (1/2x^2)^4(-3x^3/4)^2 + (1/2x^2)^3(-3x^3/4)^3 + (1/2x^2)^2(-3x^3/4)^4 +
(1/2x^2)(-3x^3/4)^5 + (-3x^3/4)^6