The universal law state thsat the volume of a given mass of an ideal gas varies directly with its pressure(pnm^2) a certain mass of a gas at an absolute temperature 275k and pressure 10^5Nm^-2 has a volume of 0.0225m3
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QUESTION: find the pressure of a gas when its absolute temperature is 374k and its volume is 0.018m^3.

The universal law state that the volume of a given mass of an ideal gas varies directly with its pressure(pnm^2) a certain mass of a gas at an absolute temperature 275k and pressure 10^5Nm^-2 has a volume of 0.0225m3.

The General Gas Equation is;

P1*V1/T1 = P2*V2/T2

where we have

P1 = 10^5 Pa

V1 = 0.0225 m^3

T1 = 275 K

P2 = ?

V2 = 0.018 m^3

T2 = 374 K

Equating the two sets of values,

10^5 * 0.0225 / 275 = P2 * 0.018 / 374

P2 = 10^5 * (0.0225/0.018) * (374/275) = 1.7 * 10^5

P2 = 170 KPa

by Level 11 User (81.5k points)

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