Question: Find the intecepts of the straight line -2y+x=2y-8.
1st, let's put the equation into standard form.
-2y+x=2y-8 -- add 2y to both sides
x = 4y - 8 -- divide by 4
(x/4) = y - 2 -- rearrange
y = (x/4) + 2 -- standard form: "y = mx + c", where m is the slope with m = 1/4. and c is the y-intercept
The y-intercept is where the straight line cuts the y-axis, and when the line cuts the y-axis, this is at x = 0.
The x-intercept is where the straight line cuts the x-axis, and when the line cuts the x-axis, this is at y = 0.
With y = (x/4) + 2, and x = 0, then y = 2.
So, y-intercept = 2
With y = (x/4) + 2, and y = 0, then x = -8.
So, x-intercept = -8