Question: calculate integration of log((2-x)/(2+x)) limits of integra1 to 1.
ln[(2-x)/(2+x)] = ln(2-x) - ln(2+x)
int ln[(2-x)/(2+x)] dx = int ln(2-x) - ln(2+x) dx
= {-(2-x).ln(2-x) - x} - {(2+x).ln(2+x) - x}
= -(2-x).ln(2-x) - (2+x).ln(2+x)
Integrating between the limits of x = -1 to x = 1,
I = {-(1).ln(1) - (3).ln(3)} - {-(3).ln(3) - (1).ln(1)} = {0 - ln(27)} - {-ln(27) - 0} = -ln(27) + ln(27) = 0
Answer: zero