3x^2+6x-1=0
When comparing this equation to ax^2+bx+c=0, we get a=3, b=6, c=-1
The formula x=[-b(+ or _) root of(b^2-4ac)]/2a
=[-6(+ or -)root of (6^2-4*3*-1)]/2*3
=[-6(+or -) root of (36+12)]/6
=[-6(+ or -) root of (48)]/6
=[-6(+ or -) root of (3*2*2*2*2)]/6
=[-6(+ or -) 4*root of (3)]/6
=2[-3 (+ or -)2 root of (3)]/6
=[-3(+ or -) 2 root of (3)]/3
Therefore x=[-3+2 root of(3)]/3 or x=[-3-2 root of (3)]/3