3x - 2y + 2z = 1 (ill do this answer as 3 posts)
Solving for x: 3x - 2y + 2z =1 add 2y to both sides
3x + 2z = 1 + 2y now subtract 2z from both sides
3x = 1 + 2y -2z finally divide each side by 3
x = (1 + 2y -2z)/3 or x= 1/3 + 2y/3 -2z/3
Solving for y: 3x - 2y + 2z =1 subtract 3x from both sides
-2y + 2z = 1 -3x now subtract 2z from both sides
-2y = 1-3x-2z finally divide each side by -2
y = (1-3x-2z)/-2 or y= 1/-2 - 3x/-2 - 2z/-2 y= -1/2 + 3/2 + z ( the negative signs cancel out)
SOLVING for z: 3x - 2y + 2z =1 first subtract 3x from both sides
-2y + 2z = 1 - 3x next add 2y to both sides
2z = 1-3x+2y finally divide each side by 2
z = (1-3x+2y)2 or z= 1/2 - 3x/2 + 2y/2 z=1/2-3x/2+y