then,
log(y+2)^2 =log(y+2)/13
(y+2)^2 =(y+2)/13
13(y+2)^2 =(y+2)
13(y+2)^2-(y+2)=0
(y+2)[13(y+2) - 1]=0
(y+2)[13y+26-1]=0
(y+2)[13y+25]=0
y=-2 but this answer is excluded since you cannot take the log of zero.
y=-25/3 answer also excluded since you cannot take the log of a negative