how to I find the zeros of 5y^3-3y^2+8y=0?

Please help me answer this. It is a poly nomial function. I need to find the zeros.
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1 Answer

Factorise:

y(5y²-3y+8)=0.

Solve the quadratic using the formula: y=(3±√(9-160))/10=(3±√-151)/10.

This produces a complex solution: y=0.3±i√151/10

The zeroes are 0, 0.3+i√151/10, 0.3-i√151/10.
by Top Rated User (1.1m points)

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