1+tan^2(x)=sec^2(x) and the derivative of tan(x) is sec^2(x). Integral of tan^2(x) is integral of sec^2(x)-1, which integrates to tan(x)-x. Apply the limits: tan(1.05)-1.05-(tan(0)-0)=1.7433-1.05=0.6933 approx. (For angles we need to consider radians rather than degrees, where 180 degrees is (pi) radians=3.1416 approx. So 1.05 is equivalent to 60.16 degrees.)