find the solution set of the exponintial equation: x^x^x=2
asked Mar 22, 2015 in Algebra 1 Answers by mnmn

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1 Answer

Given x^x^x=2

Take log on both side

log x^x^x=log 2

x^x log x=0.693

Solve for x

x=1.476616


Get free help for Exponential Function Equation

answered Mar 23, 2015 by John Marsh Level 8 User (30,400 points)

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