Until the table is provided, only a general answer can be given. Let's suppose that one loop is the set of objects with property A, and the second loop that with property B. Forgetting about the triangle for a moment, the intersection of the loops is the set of objects with properties A and B. Now, introduce the triangle. By itself it represents the set of objects with property C. But because it's within the intersection of the loops, C is a subset of the set of objects with properties A and B. As a subset it can only contain objects with properties A and B and it does not contain all such objects. In fact, the area outside the triangle but within the intersection of the two loops represents the set of objects with properties A and B but excludes those contained by the triangle. The Venn diagram contains 4 regions:
- A objects only
- B objects only
- A and B but not C
- A, B and C objects
Let's use an example. A objects are red; B objects are square; C objects are striped.
The 4 regions are:
- Red objects that are neither square nor striped
- Square objects that are neither red nor striped
- Square red objects that are not striped
- Square striped red objects
The loops can be labelled RED and SQUARE and the triangle can be labelled STRIPED.
By substituting other properties for red, square, striped, the diagram can be used to solve sorting problems.
Let's substitute LARGE for striped. The triangle represents large objects. Both loops contain some large objects. The 4 regions become:
- Small red objects that are not square
- Small square objects that are not red
- Small red square objects
- Large red square objects.
The loops can be labelled RED and SQUARE, and the triangle can be labelled LARGE.