log8(x^2-30)=log8(x)
raise both sides to the 8th power to cancel out the log
your left with x^2-30=x subtract x from both sides
x^2 - x - 30 =0
(x-6)(x+5)
x= 6, -5
now that a property of log allows us to raise it by the base to cancel out the log for example:
log812=1 if we raise both sides to the 8th power it would look like this:
8^log8(12) = 8^1 the 8 and log 8 cancel out
12=1 which is not correct at all... 8 does not equal 1... hmm mabe i should have thought this problem out more lol but you get the idea :s