(4-3i/7)+2/7+8i-(4-2i)
4 - 3i/7 + 2/7 + 8i - 4 + 2i
4 + 2/7 - 4 - 3i/7 + 8i + 2i
2/7 + i(10 - 3/7)
(1/7)(2 + 67i)
The complex number evaluates to: 2/7 + 67i/7
The complex conjugate of the number (a + bi) is (a - bi).
The complex conjugate of the above solution is: 2/7 - 67i/7