6 was added to some number. This sum was then multiplied by 6 and that product was then divided by 3 for a result of 4. What was the initial number?
Let tne initial number be N.
N + 6 (6 was added to some number)
(N + 6)*6 (This sum was then multiplied by 6)
(N + 6)*6 / 3 (that product was then divided by 3)
(N + 6)*6 / 3 = 4 (for a result of 4)
(N + 6)*2 = 4
N + 6 = 2
N = -4