If (x-5)/4 is 3 Less than (7+x)/5
Let A = (x-5)/4
Let B = (7+x)/5
Then we cam rewrite the original question as: if A is 3 less than B
And we can write that as the following equation: A = B - 3 (A is 3 less than B is)
Substituting back in for the values of A and B gives us,
(x - 5)/4 = (7 + x)/5 - 3
Multplying both sides by 20 (because 4 * 5 = 20)
5(x - 5) = 4(7 + x) - 60
5x - 25 = 28 + 4x - 60
5x - 4x = 28 + 25 - 60
x = 53 - 60
x = -7