A friend of mine asked if i can solve her this question and never respponded that i dont know calculos so i dont want to let her fail so can you answer this quick please?
in Calculus Answers by Level 1 User (920 points)
PLeaassse  o one answered yet oh come ON jishka Jomework ansers answer FAST!

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

First, we need to find out where the curve meets the x-axis (y=0), so it’s clear that x=0 and x=3 are the limits.

We can write the area as an integral: ∫ydx[0,3] where the limits are in square brackets.

Substitute for y: ∫(3x⁵-x⁶)dx=(x⁶/2-x⁷/7)[0,3]=3⁶(1/2-3/7)=729/14=52¹⁄₁₄ or 52.07͒14285͒ where   ͒  indicate a recurring  decimal.

The curve in red is a thin sliver between x=0 and x=3 as shown. The required area is clearly seen.

by Top Rated User (598k points)

Related questions

0 answers
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
81,947 questions
86,330 answers
2,238 comments
71,543 users