A friend of mine asked if i can solve her this question and never respponded that i dont know calculos so i dont want to let her fail so can you answer this quick please?

First, we need to find out where the curve meets the x-axis (y=0), so it’s clear that x=0 and x=3 are the limits.

We can write the area as an integral: ∫ydx[0,3] where the limits are in square brackets.

Substitute for y: ∫(3x⁵-x⁶)dx=(x⁶/2-x⁷/7)[0,3]=3⁶(1/2-3/7)=729/14=52¹⁄₁₄ or 52.07͒14285͒ where ͒ indicate a recurring decimal.

The curve in red is a thin sliver between x=0 and x=3 as shown. The required area is clearly seen.

- All categories
- Pre-Algebra Answers 12.3k
- Algebra 1 Answers 25.3k
- Algebra 2 Answers 10.5k
- Geometry Answers 5.2k
- Trigonometry Answers 2.6k
- Calculus Answers 6.1k
- Statistics Answers 3k
- Word Problem Answers 10.2k
- Other Math Topics 6.7k

81,947 questions

86,330 answers

2,238 comments

71,543 users