The first thing to do is to rearrange the equation into standard form: 3y=5x-15. Now divide through by 3: y=5x/3-5. We only need two points to draw a straight line graph. The normal process is to find the intercepts, that is, the points where the line cuts the axes. To find the y intercept, where the line cuts the y axis, we put x=0. That means we mark the point -5 on the y axis. If we put x=0 in the original equation we get: 3y=-15 and so y=-5, the same result. To find the x intercept we put y=0. If we do this in the original equation we get: -5x=-15 so x=3. That's probably easier than putting y=0 in the rearranged equation, but the result is the same: 5*3/3-5=0. So we mark the point 3 on the x axis.now we can draw a line through the two intercepts and that's the graph. The slope of the graph is 5/3, and the y intercept, as we've seen. The standardised equation exposes the slope and intercept whereas the original equation didn't. The slope is bigger than 1, so it's steeper than 45 degrees and it slopes to the right, a positive slope.