The perimeter of a rectangle is 200 yards. What are the dimensions of the rectangle if the length is 20 yards more than the width?
2W + 2L = perimeter
Given: L = 20 + W and perimeter = 200
Substitute this into the formula for L
2W + 2(20 + W) = 200
2W + 40 + 2W = 200
4W + 40 = 200
4W = 160
W = 40
substitute this value for W back into the equation to find L
L = 20 + W
L = 20 + 40
L = 60
check:
2W + 2L = perimeter
2(40) + 2(60) = 200
80 + 120 = 200
200 + 200