7×6=42, 7×16=112, 7×26=182, etc.
The multiples of 7 form a series: 42+70(n-1).
We need to solve for n: 42+70(n-1)<900.
42+70n-70<900,
70n<928,
n<13.26, so n=13 maximum.
42+70×12=882.
So there are 13 numbers divisible by 7 ending in 2:
42, 112, 182, 252, 322, 392, 462,
532, 602, 672, 742, 812, 882.