dy/dx=-12(3-x)¹¹=-12(3-2)¹¹=-12 at (2,1) is the gradient of the tangent and 1/12 the gradient of the normal.
The equation of the tangent line is y-1=-12(x-2), y=-12x+25;
The equation of the normal line is y-1=(1/12)(x-2), 12y-12=x-2, so y=(1/12)(x+10).