1. Assume this is 3/(5y-11)=8/(3y+4).
Cross-multiply: 3(3y+4)=8(5y-11).
Expand brackets: 9y+12=40y-88.
Subtract 9y from each side: 12=31y-88.
Add 88 to each side: 100=31y so y=100/31.
2. Assume (3/5)y-11=(8/3)y+4.
Multiply through by 15: 9y-165=40y+60.
Add 165 to each side: 9y=40y+215.
Subtract 40y from each side: -31y=215 or 31y=-215, y=215/31.
3. Another interpretation: assume 3/(5y)-11=8/(3y)+4.
Multiply through by 15y: 9-165y=40+60y.
-215y=31, y=-31/215.
The solution depends on which interpretation is intended.