substitute (x,y)=(2,1) and check if it satisfies the equation
If it does then it is a solution.
3x+y=3(2)+1=6+1=7
7 is not equal to 10 ,so (2,1) is not a solution of the equation.
2x+12y=2(2)+12(1)=4+12=16
Not a solution .
(2,1) will not lie on the graph .