Prove that its right.
asked Jul 20, 2012 in Trigonometry Answers by anonymous

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1 Answer

(cscA)(sin2A) - secA = (cos2A)(secA)

LHS=(cscA)(sin2A) - secA



=2cosAsecA/secA  -secA

=2 cos^2(A)secA-secA

=(2 cos^2(A) - 1)secA





answered Jul 20, 2012 by soudhamini Level 5 User (14,740 points)
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