-2 + 6y = 13x + 2
6y = 13x + 4
y = (13/6)x + 2/3
slope = 13/6
perpendicular slope = -6/13
we want the equation of a line with slope = -6/13, passing through point (-2,-4)
point-slope form
y - y1 = m (x - x1)
y - -4 = (-6/13) (x - -2)
y + 4 = (-6/13) (x + 2)
y + 4 = (-6/13)x - 12/13
y = (-6/13)x - 12/13 -4
y = (-6/13)x -64/13