What is the size of the exterior angle of a regular 22 sided polygon?
The only formula I could find is for the sum of the interior angles of a polygon:
IA = (n - 2) 180; n is number of sides.
IA = (22-2)180
IA = 20*180
IA = 3600 this is the total measure of all angles
3600/22 = one angle = 164 degrees
this is the outer angle also.