Can someone explain the easiest way to tell? Thanks.
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9 Answers

if coefficient on x^2 is positive, it opens up, if negative, it opens down.

Since x^2 increases faster than x, for very high x the function will go in the same direction as the sign on x^2.

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ax^2 +bx +c= 0

If a is positive, opens up. If a is negatives, opens down.
how to solve 33 devided by 429 is what?
by Level 1 User (200 points)

You are retarted. Even I can answer this question and I'm in 5th friggin grade!!!!no

by
how to turn a fraction into a mixed number
by

If the coefficient of x^2 is positive, then the parabola is opening up. 

If it is negative, it opens down.

the graph of 2x^2 + 2x + 2 would open up, but the graph of -2x^2 + 2x + 2 would open down.

(those were NOT real examples, I put them just to illustrate the concept) smiley

 

 

by
Think of it this way, Up starts with U. So if the parabola is opening up it looks like a U. Down ends with N so if the parabola looks like a lower case N then its opens down. Hope it helps
by
how to convert 3883.982143 into a mixed fraction, and show me your break down, thanks.
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(4+5)(4-5)
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The graph of a quadratic function, y=ax²+bx+c (a≠0), is a smooth curve called parabola that is symmetric with respect to a vertical line called the axis of symmetry.   The axis intersects the parabola at a point called the vertex, turning point of the curve, where the curve takes the maximum or minimum value.

To find whether the curve "opens up" or "opens down", change the standard form above into a vertex form such as y=a(x-d)²+e (a≠0), and examine the values of y on both sides of the axis of symmetry.   The line x=d is the axis of symmetry, and coodinates of the vertex is x=d and y=e,(d,e).

Notice the first term a(x-d)², where (x-d)²≥0.   So, if a>0, then a(x-d)²≥0 and y increases as x increases or decreases on both sides of the axis of symmetry.   Thus the parabola opens up(holds water) and takes the minimum, y=e, at the vertex, x=d.

If a<0, then a(x-d)²<0 and y decreases as x increases or decreases on both sides of the axis of symmetry.   Thus, the parabola opens down(spills water) and takes the maximum, y=e,at the vertex.

Therefore, the parabola: y=ax²+bx+c, opens up if a<0, or opens down if a<0. 

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