Since x = -2y+3 and x = 3y - 7 you can set the 2 expressions equal to each other like this:
-2y+3 = 3y - 7 and solve for y.
Add 2y to each side:
3 = 5y - 7
Add 7 to each side:
10 = 5y
Divide both sides by 5:
2 = y.
Now that you know that y = 2, substitute the 2 back into either original equation:
x = -2(2)+3
x = -4+3
x = -1
The point where the systems cross is (-1, 2)