how do i solve this equation using the substitution
method y=5x-2, 2x+9y=10
In the first equation, you already have y in terms of x.
Substitute that into the place of y in the second equation.
2x + 9(5x-2) = 10
2x + (45x - 18) = 10
2x + 45x - 18 = 10
47x = 10 + 18 = 28
x = 28/47
Now, substitute that value of x into the first equation.
y=5x-2
y = 5(28/47) - 2
y = (140/47) - 2 Note: 2 = 94/47
y = (140/47) - (94/47)
y = 46/47