1 | 1 1 0 -2
1 1 2 | 2
1 2 2 | 0 = x2+2x+2
x3+x2-2=(x-1)(x2+2x+2), therefore:
(x3+x2-2)/(x-1) simplifies to x2+2x+2 when x≠1, which is the domain.
Limit as x→1 is 1+2+2=5 although the point (1,5) is undefined for the original expression.
For most intents and purposes, the expression x2+2x+2 is a valid substitute and the domain is unbounded. (The range is restricted to [1,∞).)