The Product of two consecutive even integers is 80. Find the two integers.
Let the two numbers be 2n and (2n+2)
Then we have,
2n*(2n+2) = 80
n(n + 1) = 20
n*2 + n - 20 = 0
(n - 4)(n + 5) = 0
n = 4, n = -5
Giving a solution for positive integers only, then n = 4
Answer: the two numbers are 8 and 10