(1) 2=log3(9), so 1log3(x+5)-2=log3(5) is the same as:
log3(x+5)-log3(9)=log3(5), log3[(x+5)/9]=log3(5), therefore:
(x+5)/9=5, x+5=45, x=40.
(2) 4log3(x)=64. Take logs to the base 4:
log3(x)=3, x=33=27.
(3) 27log3(x)=8, 33log3(x)=23. Taking logs to base 3:
3log3(x)=log3(23)=3log3(2), log3(x)=log3(2), x=2.