me assume that stuf spozed tu be
line 1: (a/x) +(b/y) =(a/2) +(b/3)
or ay +bx =(axy/2) +(bxy/3), or 6ay +6bx=3axy+2bxy
line 2: x-y=-1, bekym y=x+1
put line2 in line1... 6a(x+1) +6bx = 3ax(x+1) +2bx(x+1)
3ax^2 +3ax +2bx^2 +2bx -6ax -6a -6bx=0
(3a+2b)x^2 +(3ax+2bx -6ax) -6a=0
(3a+2b)x^2 +(-3a+2b)x -6a=0
if yu suppli numbers for a & b, me kood solv that