Solve the equation for y.

2y^2+9y+35=(y+7)^2

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1 Answer

2y^2 + 9y + 35 = (y + 7)^2

2y^2 + 9y + 35 = y^2 + 14y + 49

y^2 - 5y - 14 = 0

(y - 7)(y + 2) = 0

y = 7 or -2
by Level 13 User (103k points)

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