For real numbers p, q and r, given that p/q = q/r = r/p , show that p+q+r = 0

pq+qr+rp =0
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1 Answer

haha, i just answered my own question p/q = q/r change into pr= q^2 q/r = r/p change into qp = r^2 q^2 - r^2 = p ( r - q) (q+r) (q-r) = -p (q-r) q+r = -p therefore, p+q+r = 0
by Level 3 User (4.4k points)

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