what is the axis of symmetry,vertex,and y intercept of the quadratic equation y=x^2--8x+2

Question

finding the axis of symmetry,vertex,and y intercept of the quadratic equation

Answer 1

?????????????? "vertex" ???????????? . . . ??? yu wanna find the hi or lo ???? . . . me assume yu mistiped, & that stuf shood me . . . x^2 -8x +2=0 . . . roots=7.7416574 & 0.2583426=zeroes=weer y=0 . . . =weer kerv hit or kross x-axis . . . Tu get the lo or hi...dy/dx=2x-8 & set it tu 0. . .. 2x-8=0, 2x=8, x=4 . . . point=(4,-14) . . . kerv=parabola with vertikal axis