WHATS THE PERPENDICULAR LINE OF -X-3Y=-15;(-2,3)
prependicular to the given line and that passes through the given point
-X - 3Y = -15
-3Y = X - 15
Y = -(1/3)X + 5
The slope of this line is -1/3; the slope of a line perpendicular to
this one is 3.
The equation for the perpendicular line is y = 3x + b
To pass through (-2,3),
b = y - 3x
b = 3 - 3(-2)
b = 3 + 6
b = 9
That makes the equation y = 3x + 9