got this in my maths homework, please help! (optimization)

Question

the company 'your other national drink' are trying to cut costs and they reckon they can make their 330ml can using less aluminium. Assuming the can is a simple cylinder and it has to hold a volume of 330ml (330cm3) what is the best size to make it so that it uses as a little aluminium as possible? (You need to give the height and radius of the base)

Answer 1

kost av kan=metal for the skin, so kost=konstant*aea av kan . . . so yu need tu minimize area/volume . . . tin kan=cylinder . . . .....volume=(base area)*hite & base area=pi*radius*radius . . . area=sides +2 ends . . . side=hite*2*pi*radius . . . 1 end area=pi*radius+radus . . . area=2*pi*radius*hite + pi*radius*radius . . . area=pi*radius*(2*hite +radius) . . . area / volume=pi*radius*(2*hite+radius) / pi*radius*radius . . . =(2*hite+radius)/radius . . . also hav rule...volume=konstant=base*hite . . . if yu inkreez hite, gotta kut area & also the opposut . . . in other werds, d(hite)=-d(base area ) d=0 at hite=radius/2