How do i solution it?

Question

-solving line equation y=6(-8-x)-6, -2(x+2)=-2+2y -calculating slope and y-intercept 4+x=4(y+3) -6(y-2)=-24-x find a perpendicular a line containing a given point 4(x+4)=2x-y (-4,-4),-3+y=-4(x+8) (-3,7) find a parallel line containing a given point 7-y=8(1-2x) (-2,8), 2(y-5)=6-5x (-6,-3) also,i need show the work,help me please!!!

Answer 1

line 1: y=6(-x-8)-6...y=-6x -54 . . . line 2: -2(x+2) =2y-2, or 2y-2=-2x-4, 2y=-2x-2, y=-x-1 . . . thus, 6x-54=-x-1 . . . 7x=53 . . . x=53/7=7.57142857142857... from line 2...y=-x-1=-(53/7)-1=-60/7=8.57142857142857... thats weer 2 lines meet . . . .