i have two equations  xe^xy+1=0 and ye^xy+1 how do i solve for x?
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1 Answer

You have supplied only one equation so let’s assume the second expression is equal to a.

From the first equation, e^(xy)=-1/x and from the second equation e^(xy)=(a-1)/y.

So -1/x=(a-1)/y. Cross-multiply: -y=x(a-1) making x=-y/(a-1) for all a except a=1.

For example, if a=2, x=-y. If a=0, x=y.

If the second expression had been ye^(xy)=1 then this is the same as ye^(xy)+1=2 so this makes a=2 and the solution would be x=-y.

by Top Rated User (1.1m points)

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