can you solve (x^2)(y^2)(4-x^2)(4-y^2) be great than equal to 16?
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1 Answer

x^2*y^2 part giv a positiv number that kan get very big if x or y get big

the other part...(4-x^2)*(4-y^2) is same as [-(x^2-4)]*[-(y^2-4)]

2 minus sines kansel, so it become (x^2-4)*(y^2-4)

& that be...(x-2)(x+2)(y-2)(y+2)

if x or y get big, that thang kan get plenty big...big as yu want
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