Consider the function f(x)=3x2−4x+3,0≤x≤7, what is the absolute maximum and absolute minimum

Question

Consider the function f(x)=3x2−4x+3,0≤x≤7. The absolute maximum of f(x) (on the given interval) is? and the absolute minimum of f(x) (on the given interval) is?

Answer 1

y=3x^2 -4x+3

quadratik equashun giv komplex roots

dy/dx=6x-4, so slope=0 at x=2/3 ....y=1.66666 point=(0.66666,1.6666)

at x=0, y=3...bigger, so that impli x=2/3 is the lo

at x=7, y=122...thats the hi