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I assume the region is being rotated around the y-axis (x=0).

Imagine a thin cylindrical shell of radius x and height h with the y-axis through its centre. The circumference of the cylinder (top and base) is 2πx.

If this cylinder is laid out as a thin rectangular lamina its dimensions would be 2πx by h, and its volume 2πxhdx, where dx is the thickness of the shell/lamina.

But h=e³ˣ-eˣ, so the volume is 2πx(e³ˣ-eˣ)dx. The sum of all such infinitesimally thin shells between x=0 and x=1 is:

2π∫₀¹x(e³ˣ-eˣ)dx.

Consider ∫xeⁿˣdx. Let u=x, then du=dx; and dv=eⁿˣdx, then v=eⁿˣ/n. Integrating by parts:

∫udv=uv-∫vdu=xeⁿˣ/n-(1/n)∫eⁿˣdx=xeⁿˣ/n-(1/n²)eⁿˣ.

So, setting n=1 and n=3:

2π∫₀¹x(e³ˣ-eˣ)dx=

2π[(xe³ˣ/3-(1/9)e³ˣ)+(xeˣ-eˣ)]₀¹=

2π(2e³/9+e-1/9+1)=2π(2e³/9+e+8/9)=50.71 cubic units approx.

by Top Rated User (1.1m points)

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