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Let g(x)=X^2 -3x +8 find the value of g(-2)

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Let g(x)=X^2 -3x +8 find the value of g(-2)

please help me with this

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asked Nov 15, 2013 in Algebra 1 Answers by anonymous

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2 Answers

g(x)=X^2 -3x +8

g(-2)=(-2)^2-3(-2)+8

g(-2)=4+6+8

g(-2)=18

answered Nov 15, 2013 by memi Level 1 User (180 points)

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g(x) = x^2 - 3x + 8

Put -2 in place of x in the given equation,

g(-2) = (-2)^2 - 3*(-2) + 8

= 4 + 6 + 8 = 18.

So, g(-2) = 18.

answered Nov 15, 2013 by SubjectTeachers Level 1 User (380 points)

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