x²+y²=24 y=2x+3

mathematics a complete course with cxc questions volume two exercise 13m # 11
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1 Answer

Substitute y from the second equation in the first equation: x^2+(2x+3)^2=24, so x^2+4x^2+12x-15=0.

5x^2+12x-15=0. Solve using the formula: x=(-12+sqrt(144+300))/10=0.9071 or -3.3071.

Therefore y=2x+3=4.8143 or -3.6143.

Check: 0.9071^2+4.8143^=24; 4.8143=2*0.9071+3;

(-3.3071)^2+(-3.6143)^2=24; -3.6143=2*(-3.3071)+3.

Two solutions: (0.9071,4.8143) and (-3.3071,-3.6143).

by Top Rated User (1.1m points)

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