(4y^2-y-3)/(8-7y+y^2)

how do i solve this
in Algebra 2 Answers by Level 1 User (680 points)

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2 Answers

4y^2 -y - 3         (4y + 3) (y - 1)

----------------- = -------------------

y^2 - 7y + 8       y^2 - 7y + 8

 

by Level 10 User (55.7k points)
solve 1/3(4y-2)-(3y-1-4y/2)=y=5/2
by

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