Prove that (3+cot 76 cot 16)/(cot 76 + cot 16)= tan 46

prove that

3+cot 76 cot 16/(cot 76 + cot 16)   =tan 46
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1 Answer

lhs= (2sin76sin16+cos(76-16))/sin(76+16)

=(cos(76-16)-cos(76+16)+cos60)/sin92

=(1-cos92)/sin92=2sin^2(46)/2sin46cos46=tan46=cot44

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