solve this equation sin h2 = 2sinh 2coshz
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I think this is supposed to be the identity:

sinh(2z)≡2sinh(z)cosh(z).

sinh(2z)=(e2z-e-2z)/2; sinh(z)=(ez-e-z)/2; cosh(z)=(ez+e-z)/2;

therefore, sinh(z)cosh(z)=(e2z-e-2z)/4=½sinh(2z), and sinh(2z)=2sinh(z)cosh(z) QED.

by Top Rated User (1.1m points)

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