
In the Venn diagram shown above the letters mean the number of farmers growing:
A only wheat
B only corn
C only oats
D only wheat and oats
E only corn and oats
F only wheat and corn
G wheat, corn and oats
H none of wheat, corn or oats
Now we put figures to these:
A=125, B=110, C=90;
A+D+F+G=200 (wheat farmers);
F+G=60 (wheat and corn farmers), D+G=50 (wheat and oat farmers);
B+E+F+G=180 (corn farmers);
A+B+C+D+F+G+H=500.
Now we work out more figures.
A+D+F+G=200 and F+G=60, so A+D=140, and since A=125, D=15. D+G=50, so G=35.
B+E=180-60=120, E=120-110=10; F=60-35=25.
Summary so far: (A,B,C,D,E,F,G)=(125,110,90,15,10,25,35). All that remains is H.
A+B+C+D+E+F+G=410, so H=500-410=90.
Q1) 410 grew at least one of the three
Q2) 35 grew all three
Q3) 90 grew none of the three
Q4) D+E+F=15+10+25=50 grew two out of three
Q5) The solution method is explained above (including the diagram)