Find the dimensions of a rectangle whose perimeter is 96 meters and whose area is 40 square meters.

Find the dimensions of a rectangle whose perimeter is 96 meters and whose area is 40 square meters.

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1 Answer

rektangel, area=40, rim-leng=96

half-rim=48=leng+wide

thus, wide=48-leng

area=leng*wide=40=leng*(48-leng)

-leng^2 +48leng-40=0....or leng^2 -48*leng+40=0

quadratik equashun giv zeroes=0.8483262 & 47.1516738

1=leng, other=wide
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